Sunday, October 02, 2011
Riemann Hypothesis Solved Using A Quantum Mechanical System
Riemann's Hypothesis is that all the non-trivial zeros lie on the line ( y = ½ ) and these zeros have something to do with prime numbers. Since Riemann's Hypothesis includes the line ( y = ½ ), let's chose a quantum energy system in which the energy levels are 2. Riemann's equation also included complex numbers. In a quantum energy system Riemann's complex numbers could be represented by zero's ( 0 ) since ( 2 + 0 = 2 ). ( 1 + 1= 2 ) also equals 2. Riemann also went on to say that the prime number locations were influenced by the position of the zeros. To extend our ( 1 + 1 = 2 ) analogy, we now have ( 1 + 0 + 1 = 2 ). We can convert these additions to numbers ( 11, 101, etc. ). We can now say that we have a real axis ( y = 2 ) with infinite numbers with zeros between their ones ( 11, 101, 1001, 10001, etc. ) on an infinite real axis line ( y = 2 ). These numbers would also be evenly spaced on the real axis line ( y = 2 ) since each infinite number would total energy level 2 which means the distance between the numbers would be ( 2 + 2 = 4 ) or a spacing of 4. Riemann's Hypothesis says that all his formula's non-trivial zero's are on the line ( y = ½ ). If we flip our infinite real axis line ( y = 2 ), we create a real axis line ( y = ½ ) with flipped infinite real numbers ( 1/11, 1/ 101, 1/1001, etc. ) all the way to infinity. If we add ( ½ + 1/11+ 1/ 101 + 1001 + etc. ) we eventually start to get numbers resembling ( .509999. .500999, etc. ) The zeros in these numbers are Riemann Zeros and the 9's are Riemann 9's. If you raise these numbers to the power of 2, you get somewhere over ¼ . As a matter of interest prime number 97 is the 26th prime. If you multiply ( 97 X ( .5099999 ) X ( .5099999 ) you get very close to 26. The calculation of the prime numbers are a little bit more complicated than this illustration but this is the basics.