## Wednesday, November 30, 2011

### The Quantum World

The quantum world is made up of individual particles that don't have to travel through space to go somewhere. This world looks like foam continuously bubbling away. Travel in the quantum world is through the action of cloning, superposition and entanglement. Cloning is the method by which the individual particle reproduces itself at new locations. Superposition means that more than one particle can occupy the same space at the same time because space hasn't a physical reality in the quantum world. Quantum particles don't have to travel through space to get from A to B because space doesn't exist. Entanglement is the method by which a particle transfers information from one point to another point . A quantum particle can bubble many copies of itself at the same approximate location. This means that the bubbling quantum particle at the new location forms a cloud. This cloud may also appear as a wave which we can measure. We can also measure the position of the quanta, but we can't do both measurements at the same time. Different quanta may come together to form units of something else. If these quanta can't be separated out then we say a strong nuclear ( cloud ) force exists between them. This strong nuclear ( cloud ) force can also be considered as an unbreakable wave. If these quanta can be separated out in a reaction then we can say it has a weak nuclear force and a breakable wave that forms relationships with other quanta. Sometimes quanta form a rotational cloud with each other and these clouds carry plus and minus charges. These are your electromagnet quanta forces.

## Tuesday, November 22, 2011

### Time

Time is the basis of everything. When the universe was initially created, time separated out into dark matter, dark energy and string space. Dark matter acts like a thick honey which tends to keep everything in its' place like inertia. Dark Energy acts as an accelerator for the universe. String space when forming circles creates things and the string's circular vibration creates different characteristics which we see as that thing's properties. Unattached curved strings, when vibrating, appear to us a waves which when modulated transmit information. Radios use that technology. A non-vibrating curved string is gravity or mass. Inertia is related to the mass of the object. Spaceless time from another universe that existed before the creation of our universe is now our quantum world. In the quantum world there is time but not space. Einstein spoke of spooky action at a distance which is true in the abstract but not existing physically. If space doesn't exist in the quantum world, you don't have any delays. The absence of space means you can have superposition because more than one thing can exist literally on / in the same spot. You can also have entanglement which means that if something happens in one location the something immediately happens / clones in the other location. This happens because the something doesn't have to travel through physical space. The speed of change is infinite ( timeless ), because the limitation on the speed of light only applies when it is moving through space and not time. To take it one step further, suppose that something went wrong and spaceless time in another universe cloned space creating an expanding bubble resulting in our universe. Since our space includes classical time, and at the time of the creation of our universe everything wasn't immediately converted there would be more space than we first calculated from our perspective of logical events. Also not all the time would be converted which meant dark time, dark matter and dark energy still exists. In fact there is much more dark time, dark matter and dark energy in comparison to matter and anti-matter.

## Friday, November 18, 2011

### Holographic Projections, Black Holes & Event Horizons

The whole universe is organized and run by time which has a mathematical value of nine ( 9 ). Space is composed of a series of strings whose basic value is one to nine ( 1 – 9 ). The zero ( 0 ) string holds imaginary numbers. Everything that isn't time, is associated with a string that is equal to the one digit sum of its' digits . For instance ( 97 ) contains the digits 9 and 7 which total 16 ( 9 + 7 = 16 ) 16 contains the digits 1 and 6 which total 7 ( 1 + 6 = 7 ). Therefore something with the value of 97 rests on the 7th string. If you take the numbers from 1 to 99, and add the digits until one digit is left you will find that the sequence of the one digit numbers go from 1 to 9 and then repeat themselves. These strings can be thought of as strings of space. These space strings rest on a complex woven background string whose value is zero ( 0 ) and is equivalent to imaginary numbers since you can't show any values on string zero ( 0 ) except zero ( 0 ). The world around us ,including you and I, appears to be solid because our vision can't see finer detail on its' own. You and I including the quantum world is really like a swarm of flies. If you look at a swarm of flies, and someone asks you its' location, you tend to answer in terms of where the densest part of the fly swarm is located. In essence when someone asks you where someone or something is located, you answer in terms where the densest part of someone or something is located. Obviously in this instance the someone or something appears solid because that is where our sight begins and ends. If everything is basically similar to a fly swarm, you can also say it is a holograph of what exists on the average at that location. Dark matter in which the universe rests is really sticky time acting as inertia and gravity while dark energy is the force of time or entropy pulling / accelerating the expansion of the universe. Dark matter as disguised time also appears to us as time or inertia which tends to keep things from falling apart. Dark energy or expanding time appears to us as entropy which tends to pull things apart which we also see as aging, force or deterioration. If you think of the universe as having direction, west to east is the expansion of the strings ( 1 to 9 ) into larger numbers totaling the value of that particular string . For instance the east to west expansion of string seven could create the value of 250 ( 2 + 5 + 0 = 7 ). The value of 250 would be on string seven ( 7 ) since the digits of ( 250 ) would total 7 ( 2 + 5 + 0 = 7 ). This east to west expansion would form a holographic pattern of information or processes which time would then project north and south which we would see as an image, process or new facts depending on our location. Time only moves outward in our universe which we see as entropy, otherwise called deterioration, force and aging. If a holographic projection reaches a black hole, the first thing it sees is an event horizon. At this point the holographic projection is changed because only time and location enter the black hole while space information stays at the event horizon. If time and location leave the holographic projection, the only thing left is the space information string 7 since ( 2 + 5 + 0 = 7 ). Thus the information at the event horizon is proportional to the area of the event horizon rather than the volume of the black hole since the black hole doesn't contain space except from our perspective. The time and location which enters the black hole from the holographic projection is a non – physical distorted quantum representation of the holographic projection without the space string which represents physical space in our seen world. Thus in a spaceless quantum world represented by time and location you get superposition, entanglement and cloning which is instantaneous. If the black hole contracts in size, time and location reverses itself and rejoins its' string which appears to us as Hawking radiation due to the creation of , to us , a new holographic projection. Time and location for the old particle is destroyed in the black hole so conservation of energy is preserved.

## Wednesday, November 16, 2011

### Holographic Universe

Let's suppose the whole universe is organized and run by time which has a value of nine ( 9 ). Everything that isn't time, is associated with a string that is equal to the one digit sum of its' digits . For instance ( 97 ) contains the digits 9 and 7 which total 16 ( 9 + 7 = 16 ) 16 contains the digits 1 and 6 which total 7 ( 1 + 6 = 7 ). Therefore something with the value of 97 rests on the 7th string. If you take the numbers from 1 to 99, and add the digits until one digit is left you will find that the sequence of the one digit numbers go from 1 to 9 and then repeat themselves. These strings can be thought of as strings of space. These space strings rest on a complex woven background string whose value is zero ( 0 ) and is equivalent to imaginary numbers since you can't show any values on string zero ( 0 ) except zero ( 0 ). The world around us ,including you and I, appears to be solid because our vision can't see finer detail on its' own. You and I including the quantum world is really like a swarm of flies. If you look at a swarm of flies, and someone asks you its' location, you tend to answer in terms of where the densest part of the fly swarm is located. In essence when someone asks you where someone or something is located, you answer in terms where the densest part of someone or something is located. Obviously in this instance the someone or something appears solid because that is where our sight begins and ends. If everything is basically similar to a fly swarm, you can also say it is a holograph of what exists on the average at that location. Dark matter in which the universe rests is really sticky time acting as inertia and gravity while dark energy is the force of time or entropy pulling / accelerating the expansion of the universe. Dark matter as disguised time also appears to us as time or inertia which tends to keep things from falling apart. Dark energy or expanding time appears to us as entropy which tends to pull things apart which we also see as aging, force or deterioration. If you think of the universe as having direction, west to east is the expansion of the strings ( 1 to 9 ) into larger numbers totaling the value of that particular string . For instance the east to west expansion of string seven could create the value of 250 ( 2 + 5 + 0 = 7 ). The value of 250 would be on string seven ( 7 ) since the digits of ( 250 ) would total 7 ( 2 + 5 + 0 = 7 ). This east to west expansion would form a holographic pattern of information or processes which time would then project north and south which we would see as an image, process or new facts depending on our location. Time only moves outward in our universe which we see as entropy, otherwise called deterioration, force and aging.

## Sunday, November 06, 2011

### Riemann's Hypothesis – Calculating Zeros On ( y = ½ )

Sometimes in life you stumble upon something that is basically true and it's up to other people to prove it. Riemann, in his Riemann's Hypothesis, said that the zeros in his hypothesis all have the value of ½ and lie on the line ( y = ½ ) . Riemann also said that the zeros can be manipulated ( positions changed or zeros added ) in order to get the primes closer to their true location. Riemann provided a formula to prove his belief which was ( s = ½ + it ). The current method of calculating the position of the zeros is by plugging numbers into the formula and calculating. I don't have any quarrel with this method except that there isn't any guarantee that you haven't missed a zero which is supposed to be on the line ( y = ½ ) and is actually off the line ( y = ½ ) . The rub in the calculation is that if you miss a “t” or an “i”, it might be the number that proves Riemann's Hypothesis is incorrect. Personally, I don't think it matters because Riemann accidentally stumbled onto something that is correct so missed numbers in “t” or “i” are academic. I don't know what numbers they are using but the available literature says the first few zeroes were calculated around 14.1344725, 21.022040, 25.010858, 30.424876, 32.935062, and 37.586178. Even if you proved that all the zeros lay on the line ( y = ½ ), that proof still doesn't tell you how all these zeros relate to the position of the primes on the line ( y = ½ ) in useable terms.

Here's my proof for what it is worth:

Riemann said that all his non – trivial zeros lie on the line ( y = ½ ) . These zeros are at the location that the primes form a right angle line to ( y = ½ ) or in other words, are vertical to the line ( y = ½ ) . Prime numbers are defined as numbers that can only be divided by themselves and ( 1 ). An example of one digit primes are ( 1, 2, 3, 5, 7 ). You can see from these numbers that primes aren't linear ( 1, 2, 3, 4 ) but form harmonics. If all the primes were played musically, you would get a tune. The physical distance between the primes would be similar to the value of the rests in a musical piece. Calculations have been done on the location that some of Riemann's zeros lie on the line ( y = ½ ) using Riemann's formula ( ½ + it ). The first few zeroes were calculated around 14.1344725, 21.022040, 25.010858, 30.424876, 32.935062, and 37.586178. These numbers are not close to the position of the beginning one digit primes ( 1, 2, 3, 5, 7 ). You will see that the distance between ( 1, 2, 3, ) is ( 1 ) and the distance between 3 & 5, 5 & 7, is 2. Riemann, in his Riemann's Hypothesis, said that the zeros in his hypothesis all have the value of ½ and lie on the line ( y = ½ ) . Riemann also said that the zeros can be manipulated ( positions changed or zeros added ) in order to get the primes closer to their true location. This manipulation changes the physical distance between the primes which is equivalent to altering the value of the rests in a musical piece.

1. 1 X .99 = .99 ( 1 )

2. 2 X .99 = 1.98 ( 2 )

3. 3 X .99 = 2.97 ( 3 )

If we add the digit ( ½ ) or ( .5 ) in Riemann's line ( y = ½ ) and Riemann's zero ( 0 ) to .99, we form the number ( .509999 ).

1. 5 X ( .509999 ) = 2.549995 (4)

2. 7 X ( .509999 ) = 3.569993 ( 5 )

3. 11 X ( .509999 ) = 5.609989 ( 6 )

This basic principle calculates the position of the primes fairly accurately up to prime 31.

Using the same multipliers on the next prime ( 37 ) we get ( 37 X .509999 = 18.869963. Prime ( 37 ) is actually the 13th prime. Riemann said that the zeros can be manipulated ( positions changed or zeros added ). We still need the ( ½ ) in Riemann's line ( y = ½ ) and the ( 9's ). If we take ( .509999 ) and multiply it by itself ( ( .509999 X .509999 = .26009898 ).

1. ( 37 X .509999 X ,509999 = 9.62366226 ( 13 )

This calculation shows that the calculated position is short of the true position by about ( 13 – 9.62366226 = 3.37633774 ). The difference is approximately equal to Pi ( 3.141592654 ). In some calculations the difference is about the natural number ( e ) ( 2.71828`828 ).

In summary, Riemann's intuition told him that the zeros had a real value of ( ½ ) which was true since the digit ( ½ ) is used in the calculation. Riemann's intuition also told him that the zeros can be manipulated ( position changed or zeros added ) which is also true. What Riemann missed was that the calculation involved the number 9 and that Pi ( 3.141592654 ) and the natural number ( e ) ( 2.718281828 ) might have to be added or subtracted from the final answer. Riemann also missed that powers would also have to be used.

In general for calculating the location of any prime you:

1. Count the number of digits in a prime number. For instance 7919 has 4 digits. Subtract 1 from the number of digits ( 4 - 1 = 3 ) for 7919. Form another number equal to the number of digits in 7919 ( 4 ) by putting ( .5 ) in the far left column and 9 in the far right column. ( .5—9 ). Fill the middle with Riemann Hypothesis zeros ( 0 ) forming a four digit number ( .5009 ). Raise ( .5009 ) to the power of 3 ( which is the number of digits in 7919 ( 4 ) minus 1 ( 4 - 1 = 3 ). ( .5009 ) ^ 3 = .125676215. Multiply 7919 X .125676215 which equals 995.2299524. 7919 is the 1000th prime. The answer is out by approximately 5. Adjust the error by adding or subtracting Pi or (e).

The Clay Mathematics Institute is offering a $1,000,000 prize for the solution to the Riemann Hypothesis. From my reading, it seems to involve proving whether or not all the zeros lie on the line ( y = ½ ) . Since I have shown how the Riemann Hypothesis relates to the location of the primes and by extension how many primes precede that prime ( counting 1, 2, 3, 4 ), it seems to me it is largely academic as to whether all the zeros lie on the line ( y = ½ ) . I have also found the missing pieces to Riemann's Hypothesis which was correct as far as it went.

Here's my proof for what it is worth:

Riemann said that all his non – trivial zeros lie on the line ( y = ½ ) . These zeros are at the location that the primes form a right angle line to ( y = ½ ) or in other words, are vertical to the line ( y = ½ ) . Prime numbers are defined as numbers that can only be divided by themselves and ( 1 ). An example of one digit primes are ( 1, 2, 3, 5, 7 ). You can see from these numbers that primes aren't linear ( 1, 2, 3, 4 ) but form harmonics. If all the primes were played musically, you would get a tune. The physical distance between the primes would be similar to the value of the rests in a musical piece. Calculations have been done on the location that some of Riemann's zeros lie on the line ( y = ½ ) using Riemann's formula ( ½ + it ). The first few zeroes were calculated around 14.1344725, 21.022040, 25.010858, 30.424876, 32.935062, and 37.586178. These numbers are not close to the position of the beginning one digit primes ( 1, 2, 3, 5, 7 ). You will see that the distance between ( 1, 2, 3, ) is ( 1 ) and the distance between 3 & 5, 5 & 7, is 2. Riemann, in his Riemann's Hypothesis, said that the zeros in his hypothesis all have the value of ½ and lie on the line ( y = ½ ) . Riemann also said that the zeros can be manipulated ( positions changed or zeros added ) in order to get the primes closer to their true location. This manipulation changes the physical distance between the primes which is equivalent to altering the value of the rests in a musical piece.

1. 1 X .99 = .99 ( 1 )

2. 2 X .99 = 1.98 ( 2 )

3. 3 X .99 = 2.97 ( 3 )

If we add the digit ( ½ ) or ( .5 ) in Riemann's line ( y = ½ ) and Riemann's zero ( 0 ) to .99, we form the number ( .509999 ).

1. 5 X ( .509999 ) = 2.549995 (4)

2. 7 X ( .509999 ) = 3.569993 ( 5 )

3. 11 X ( .509999 ) = 5.609989 ( 6 )

This basic principle calculates the position of the primes fairly accurately up to prime 31.

Using the same multipliers on the next prime ( 37 ) we get ( 37 X .509999 = 18.869963. Prime ( 37 ) is actually the 13th prime. Riemann said that the zeros can be manipulated ( positions changed or zeros added ). We still need the ( ½ ) in Riemann's line ( y = ½ ) and the ( 9's ). If we take ( .509999 ) and multiply it by itself ( ( .509999 X .509999 = .26009898 ).

1. ( 37 X .509999 X ,509999 = 9.62366226 ( 13 )

This calculation shows that the calculated position is short of the true position by about ( 13 – 9.62366226 = 3.37633774 ). The difference is approximately equal to Pi ( 3.141592654 ). In some calculations the difference is about the natural number ( e ) ( 2.71828`828 ).

In summary, Riemann's intuition told him that the zeros had a real value of ( ½ ) which was true since the digit ( ½ ) is used in the calculation. Riemann's intuition also told him that the zeros can be manipulated ( position changed or zeros added ) which is also true. What Riemann missed was that the calculation involved the number 9 and that Pi ( 3.141592654 ) and the natural number ( e ) ( 2.718281828 ) might have to be added or subtracted from the final answer. Riemann also missed that powers would also have to be used.

In general for calculating the location of any prime you:

1. Count the number of digits in a prime number. For instance 7919 has 4 digits. Subtract 1 from the number of digits ( 4 - 1 = 3 ) for 7919. Form another number equal to the number of digits in 7919 ( 4 ) by putting ( .5 ) in the far left column and 9 in the far right column. ( .5—9 ). Fill the middle with Riemann Hypothesis zeros ( 0 ) forming a four digit number ( .5009 ). Raise ( .5009 ) to the power of 3 ( which is the number of digits in 7919 ( 4 ) minus 1 ( 4 - 1 = 3 ). ( .5009 ) ^ 3 = .125676215. Multiply 7919 X .125676215 which equals 995.2299524. 7919 is the 1000th prime. The answer is out by approximately 5. Adjust the error by adding or subtracting Pi or (e).

The Clay Mathematics Institute is offering a $1,000,000 prize for the solution to the Riemann Hypothesis. From my reading, it seems to involve proving whether or not all the zeros lie on the line ( y = ½ ) . Since I have shown how the Riemann Hypothesis relates to the location of the primes and by extension how many primes precede that prime ( counting 1, 2, 3, 4 ), it seems to me it is largely academic as to whether all the zeros lie on the line ( y = ½ ) . I have also found the missing pieces to Riemann's Hypothesis which was correct as far as it went.

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